“Find all cities with more than two customers living in the city.”
SELECT customer_city, COUNT(*) AS num_customers
FROM customer GROUP BY customer_city
HAVING COUNT(*) > 2;
- Or, can write:
SELECT customer_city, num_customers
FROM (SELECT customer_city, COUNT(*)
FROM customer GROUP BY customer_city)
AS counts (customer_city, num_customers)
WHERE num_customers > 2;
🞑 Grouping and aggregation is computed by inner query
🞑 Outer query selects desired results generated by inner query
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